3.1499 \(\int \frac {1}{x^9 (1+x^8)} \, dx\)

Optimal. Leaf size=22 \[ -\frac {1}{8 x^8}+\frac {1}{8} \log \left (x^8+1\right )-\log (x) \]

[Out]

-1/8/x^8-ln(x)+1/8*ln(x^8+1)

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Rubi [A]  time = 0.01, antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {266, 44} \[ -\frac {1}{8 x^8}+\frac {1}{8} \log \left (x^8+1\right )-\log (x) \]

Antiderivative was successfully verified.

[In]

Int[1/(x^9*(1 + x^8)),x]

[Out]

-1/(8*x^8) - Log[x] + Log[1 + x^8]/8

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {1}{x^9 \left (1+x^8\right )} \, dx &=\frac {1}{8} \operatorname {Subst}\left (\int \frac {1}{x^2 (1+x)} \, dx,x,x^8\right )\\ &=\frac {1}{8} \operatorname {Subst}\left (\int \left (\frac {1}{x^2}-\frac {1}{x}+\frac {1}{1+x}\right ) \, dx,x,x^8\right )\\ &=-\frac {1}{8 x^8}-\log (x)+\frac {1}{8} \log \left (1+x^8\right )\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 22, normalized size = 1.00 \[ -\frac {1}{8 x^8}+\frac {1}{8} \log \left (x^8+1\right )-\log (x) \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^9*(1 + x^8)),x]

[Out]

-1/8*1/x^8 - Log[x] + Log[1 + x^8]/8

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fricas [A]  time = 0.84, size = 24, normalized size = 1.09 \[ \frac {x^{8} \log \left (x^{8} + 1\right ) - 8 \, x^{8} \log \relax (x) - 1}{8 \, x^{8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^9/(x^8+1),x, algorithm="fricas")

[Out]

1/8*(x^8*log(x^8 + 1) - 8*x^8*log(x) - 1)/x^8

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giac [A]  time = 0.17, size = 25, normalized size = 1.14 \[ \frac {x^{8} - 1}{8 \, x^{8}} + \frac {1}{8} \, \log \left (x^{8} + 1\right ) - \frac {1}{8} \, \log \left (x^{8}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^9/(x^8+1),x, algorithm="giac")

[Out]

1/8*(x^8 - 1)/x^8 + 1/8*log(x^8 + 1) - 1/8*log(x^8)

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maple [A]  time = 0.01, size = 19, normalized size = 0.86 \[ -\ln \relax (x )+\frac {\ln \left (x^{8}+1\right )}{8}-\frac {1}{8 x^{8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^9/(x^8+1),x)

[Out]

-1/8/x^8-ln(x)+1/8*ln(x^8+1)

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maxima [A]  time = 1.01, size = 20, normalized size = 0.91 \[ -\frac {1}{8 \, x^{8}} + \frac {1}{8} \, \log \left (x^{8} + 1\right ) - \frac {1}{8} \, \log \left (x^{8}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^9/(x^8+1),x, algorithm="maxima")

[Out]

-1/8/x^8 + 1/8*log(x^8 + 1) - 1/8*log(x^8)

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mupad [B]  time = 0.04, size = 18, normalized size = 0.82 \[ \frac {\ln \left (x^8+1\right )}{8}-\ln \relax (x)-\frac {1}{8\,x^8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^9*(x^8 + 1)),x)

[Out]

log(x^8 + 1)/8 - log(x) - 1/(8*x^8)

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sympy [A]  time = 0.17, size = 17, normalized size = 0.77 \[ - \log {\relax (x )} + \frac {\log {\left (x^{8} + 1 \right )}}{8} - \frac {1}{8 x^{8}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**9/(x**8+1),x)

[Out]

-log(x) + log(x**8 + 1)/8 - 1/(8*x**8)

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